3y^2+30y+27=0

Solution for 3y^2+30y+27=0 equation:

3y^2+30y+27=0

a = 3; b = 30; c = +27;
Δ = b2-4ac
Δ = 302-4·3·27
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-24}{2*3}=\frac{-54}{6}
=-9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+24}{2*3}=\frac{-6}{6}
=-1
$